2x^2-4x+8=-x^2+x

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Solution for 2x^2-4x+8=-x^2+x equation: 



2x^2-4x+8=-x^2+x

We move all terms to the left:

2x^2-4x+8-(-x^2+x)=0

We get rid of parentheses

2x^2+x^2-x-4x+8=0

We add all the numbers together, and all the variables

3x^2-5x+8=0

a = 3; b = -5; c = +8;
Δ = b2-4ac
Δ = -52-4·3·8
Δ = -71
Delta is less than zero, so there is no solution for the equation

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